If y=sectan-1x, then dydx at x=1.
12
1
2
Explanation for the correct option:
Find the value of dydx at x=1:
Given,
y=sectan-1x
We can write tan-1xassec-11+x2
So,
y=secsec-11+x2y=1+x2
Now differentiate with respect to x
Then,
dydx=121+x22x[∵ddxx=12x]=x1+x2
Now at x=1,
dydx=11+12=12
Hence, the correct option is A.