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Question

If y=secx+tanx, then dydx=.

A
xsecx
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B
ysecx
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C
ysinxcosx
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D
xy
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Solution

The correct option is C ysecx
Given, y=secx+tanx
on differentiating the given function with respect to x, we get
dydx = secx.tanx+sec2(x)
dydx = secx(tanx+secx)
dydx = ysecx

so the answer of given question is ysecx.

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