The correct options are
A −1, if 0<x<π
B 1, if π<x<2π
We have,sin−1(cos x)=π2−cos−1(cos x) =(π2−x, if 0<x<ππ2−(2π−x), if π<x<2π =(π2−x, if 0<x<πx−3π2, if π<x<2πClearly, it is not differentiable at x=π. Therefore,ddx(sin−1(cos x)}=(−1, if 0<x<π1, if π<x<2π