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Question

If y=sin1(6x19x2),132<x<132, then find dydx.

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Solution

Let x=13sinθ

y=sin1(6.13sinθ19132sin2θ)=sin1(2sinθ1sin2θ)=sin1(2sinθcosθ)=sin1(sin2θ)=2θ=2sin13xdydx=231(3x)2=619x2

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