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Question

If y=sin1(x1x+x1x2),0x1+52 and dydx=12x(1x)+p, then p=

A
0
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B
11x
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C
sin1x
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D
11x2
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Solution

The correct option is D 11x2
y=sin1(x1x+x1x2)y=sin1(x)+sin1(x)dydx=11x2+11x12xdydx=12x(1x)+11x2P=11x2

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