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Question

If y = (sin−1 x)2, prove that (1 − x2) d2ydx2-xdydx+p2y=0.

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Solution

Here,

y=sin-1x2Now,y1=2 sin-1x 11-x2y2=21-x2+2x sin-1x1-x23/2y2=21-x2+2x sin-1x1-x21-x2y2=21-x2+xy11-x2y21-x2=2+xy1y21-x2-xy1-2=0

Hence proved.

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