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Byju's Answer
Standard XII
Mathematics
Higher Order Derivatives
If y=sin -1 x...
Question
If y = (sin
−1
x)
2
, prove that (1 − x
2
)
d
2
y
d
x
2
-
x
d
y
d
x
+
p
2
y
=
0
.
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Solution
Here,
y
=
sin
-
1
x
2
Now
,
y
1
=
2
sin
-
1
x
1
1
-
x
2
⇒
y
2
=
2
1
-
x
2
+
2
x
sin
-
1
x
1
-
x
2
3
/
2
⇒
y
2
=
2
1
-
x
2
+
2
x
sin
-
1
x
1
-
x
2
1
-
x
2
⇒
y
2
=
2
1
-
x
2
+
x
y
1
1
-
x
2
⇒
y
2
1
-
x
2
=
2
+
x
y
1
⇒
y
2
1
-
x
2
-
x
y
1
-
2
=
0
Hence proved.
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