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Question

If y = sin (sin x) and d2ydx2+dydx tan x+f(x) = 0, then f(x) equals.

A
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B
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C
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D
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Solution

The correct option is D
dydx=cos(sin x)cos x
d2ydx2= I
I=-cos(sin x)sin xcos x[sin(sin x)]cos x
I +dydxtan x=cos2 x sin(sin x)
d2ydx2+dydxtan x+cos2 x sin(sin x)=0
f(x)=cos2x sin(sin x)

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