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Question

If y = sin x and x changes from π/2 to 22/14, what is the approximate change in y?

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Solution

Let: x=π2 x+x=2214dx=x=2214-π2=0Now, y=sin xdydx=cos xdydxx=π2= cosπ2=0y=dydxx= 0×0=0y=0

Hence, there is no change in the value of y.

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