If y - sinx 2 - cosx 22 find dydx at x - - 6

y = sin^2_(x/2) + cos^2_(x/2) + 2sin(x/2)cos(x/2) y = 1 + sinx dydx = cosx at x = π6 dydx = cos(π6) = √(3)2 ...

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Chain Rule of Differentiation

If y = sinx...

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If $y = (sin \frac{x}{2} + cos \frac{x}{2})^{2}$ find $\frac{d y}{d x}$ at $x = \frac{π}{6}$

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