CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Chain Rule of Differentiation

If y=√1+x2 ...

Question

If $y = \sqrt{1 + x^{2}}$ Find $\frac{d y}{d x}$

Open in App

Solution

$y = \sqrt{1 + x^{2}} \frac{d y}{d x} = \frac{d}{d x} \sqrt{(1 + x^{2})} \frac{d y}{d x} = \frac{1}{2 \sqrt{1 + x^{2}}} \frac{d}{d x} (1 + x^{2}) \frac{d}{d x} = \frac{x}{\sqrt{1 + x^{2}}}$

Suggest Corrections

thumbs-up

0

Similar questions

y = \frac{1}{\sqrt{a^{2} - x^{2}}}

\frac{d y}{d x}

y = {(log x)}^{cos x} + \frac{x^{2} + 1}{x^{2} - 1},

\frac{d y}{d x}

y = \sqrt{x^{2} + 1}

\frac{d y}{d x}

.

y = \frac{1}{\sqrt{(x^{2} + a^{2})} + \sqrt{(x^{2} + b^{2})}},

\frac{d y}{d x} .

If $y = \frac{1}{\sqrt{a^{2} - x^{2}}}, f i n d, \frac{d y}{d x}$ .

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Basic Theorems in Differentiation

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Chain Rule of Differentiation

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon