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Question

If y=sinx+cosx+sinx+cosx+sinx+cosx+... find the value of dydx.

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Solution

Lets call sinx+cosx as z

y=z+z+z...
y=z+y

Squaring on both sides,

y2=z+y
y2y=z
y2y=sinx+cosx

Differentiating on both wrt to x

2ydydxdydx=cosxsinx
dydx=cosxsinx2y1

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