If y-tan -14 x-1-5 x2-tan -12-3 x-3-2 x then d y-d x at x-1-5 is

The correct option is B 2.5 y = tan^ 1 (5x x/1+5x×x) +tan^ 1( 2/3+x/1 2/3×x) dy/dx = 5/1+25x^2⇒ at x=1/5 , dy/dx = 5/2 ...

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Inequalities of Integrals

If y=tan -14 ...

Question

If $y = t a n^{- 1} (\frac{4 x}{1 + 5 x^{2}}) + t a n^{- 1} (\frac{2 + 3 x}{3 - 2 x})$ then $\frac{d y}{d x} a t x = \frac{1}{5} i s$

1.5

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2.5

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Solution

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Similar questions

y = t a n^{- 1} (\frac{4 x}{1 + 5 x^{2}}) + t a n^{- 1} (\frac{2 + 3 x}{3 - 2 x})

\frac{d y}{d x}

x = \frac{1}{5}

y = {tan}^{- 1} (\frac{4 x}{1 + 5 x^{2}}) + {tan}^{- 1} (\frac{2 + 3 x}{3 - 2 x})

\frac{d y}{d x}

y = {tan}^{- 1} (\frac{4 x}{1 + 5 x^{2}}) + {cot}^{- 1} (\frac{3 - 2 x}{2 + 3 x})

\frac{d y}{d x}

{tan}^{- 1} (\frac{4 x}{1 + 5 x^{2}}) + {tan}^{- 1} (\frac{2 + 3 x}{3 - 2 x})

{tan}^{- 1} (\frac{4 x}{1 + 5 x^{2}}) + {tan}^{- 1} (\frac{2 + 3 x}{3 - 2 x})

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