If y-tan -1 ax-b - bx-a then find dydx-

y= tan^ 1( ax bbx+a) differentiating the above, #160; dydx = 11+ ( ax bbx+a)^2 . (bx+a)a (ax b)b(bx+a)^2 dydx= (bx+a)^2(bx+a)^2 + (ax b)^2×a^2+ ...

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If y=tan -1...

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If $y = {tan}^{- 1} \frac{(a x - b)}{(b x + a)}$ then find $\frac{d y}{d x}$ .

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