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Integration by Partial Fractions

If y=tan-13...

Question

If $y = {tan}^{- 1} (\frac{3 x - x^{3}}{1 - 3 x^{2}})$ , then $\frac{d y}{d x}$ , when $x ϵ (- \infty, - \frac{1}{\sqrt{3}})$ is equal to

A

- \frac{3}{1 + x^{2}}

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B

- \frac{1}{1 + x^{2}}

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C

\frac{2}{1 + x^{2}}

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D

\frac{1}{1 + x^{2}}

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Solution

The correct option is D $\frac{1}{1 + x^{2}}$
answer is C

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