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Question

If y=tan1(loge(e/x2)loge(ex2))+tan1(3+2logex16logex),then d2ydx2 is

A
2
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B
1
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C
\N
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D
-1
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Solution

The correct option is C \N
y=tan1(loge(e/x2)loge(ex2))+tan1(3+2logex16logex)=tan1(12logex1+2logex)+tan1(3+2logex13.2logex)=tan1(1)tan2(2 logex)+tan1(3)+tan1(2 logex)=tan1(1)+tan1(3)dydx=0

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