If $y = | x - a | + | x - 2 a | + | x + a |$ , then the critical point(s) for the curve is/are

- a

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a

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- 2 a

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2 a

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Solution

The correct options are
A $- a$
B $a$
D $2 a$
$y = | x - a | + | x - 2 a | + | x + a |$
When $x \geq 2 a$
$y = 3 x - 2 a$

When $a \leq x < 2 a$
$y = x + 2 a$

When $- a \leq x < a$
$y = - x + 4 a$

When $x < - a$
$y = - 3 x + 2 a$

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Similar questions

y = | x - a | + | x - 2 a | + | x + a |

The quadratic polynomial in x whose zeros are -a, 2a is:

y^{2} = 4 a x

Given the parabola $y^{2} = 4 a x,$ find the locus of intersection of pair of tangents that are perpendicular to each other

x + a = 0, y - a = 0, x + y + a = 0

x

(- 2 a, - 2 a)

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