If y-xex- then dy-dx-

Log y=e^x log x ∴1/ydy/dx=e^x log x+e^x.1/x=e^x(log x+1/x) ∴dy/dx=ye^x (log x+1/x) ...

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Logarithmic Differentiation

If y=xex, the...

Question

If $y = x^{e^{x}}$ , then $\frac{d y}{d x} =$

y (l o g x + e^{x})

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y l o g x (\frac{1}{2} + e^{x})

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y e^{x} (l o g x + x)

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y e^{x} (l o g x + \frac{1}{x})

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Solution

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