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Question

If y(x) is the solution of the differential equation
(x+2)dydx=x2+4x9,x2
and y(0)=0, then y(4)is equal to :

A
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B
0
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C
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D
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Solution

The correct option is B 0
(x+2)dydx=x2+4x9dydx=x2+4x9+44x+2dydx=(x+2)213x+2dy=[(x+2)13x+2]dxy=x22+2x13ln|(x+2)|+CPut x=0,y=0C=13ln2y=x22+2x13ln|(x+2)|+13ln2y(4)=0


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