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Question

If y=xln x, then what is the value of dydx at x=1?

A
1
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B
1e
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C
1+2e
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D
None of the above
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Solution

The correct option is A 1
The given information is:

y=xlnx

Differentiating once w.r.t to x we get,

dydx=lnx+x×1x

dydx=lnx+1

The value of the derivative at x =1 is:

y(1)=ln1+1

y(1)=1 .....Answer

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