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Question

If y=xx+xa+ax+aa, find dydx

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Solution

y=xx+xa+ax+aa

y=exlogex+xa+ax+aa

dydx=exlogex.[xx+logex]+axa1+axlogea+0

dydx=xx(1+logex)+axa1+axlogea

Hence, the answer is xx(1+logex)+axa1+axlogea.


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