Let x = 3 and x + ∆x = 2.99.
∴ ∆x = 2.99 − 3 = −0.01
y = x3 + 5 (Given)
Differentiating both sides with respect to x, we get
∴
Thus, the approximate change in y is −0.27.
If y = x3 + 5 and x changes from 3 to 2.99, then the approximate change is y is ___−0.27___.