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Question

If y = x3 + 5 and x changes from 3 to 2.99, then the approximate change is y is _________________.

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Solution


Let x = 3 and x + ∆x = 2.99.

∴ ∆x = 2.99 − 3 = −0.01

y = x3 + 5 (Given)

Differentiating both sides with respect to x, we get

dydx=3x2

dydxx=3=3×32=27

y=dydxx

y=27×-0.01=-0.27

Thus, the approximate change in y is −0.27.


If y = x3 + 5 and x changes from 3 to 2.99, then the approximate change is y is ___−0.27___.

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