If y = y(x) and it follows the relation $e^{x y} + y c o s x = 2$ , then which of the following is/are correct?

y^{^{'}} (0) = 0

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y^{''} (0) = 0

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y^{^{'}} (0) = - 1

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y^{''} (0) = 2

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Solution

The correct options are
C $y^{^{'}} (0) = - 1$
D $y^{''} (0) = 2$
Differentiate the given equation with respect to x twice

Suggest Corrections

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| y^{'} (0) |

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