CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If y=y(x) is the solution of the differential equation 5+ex2+ydydx+ex=0 satisfying y(0)=1, then a value of y(loge13) is:

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1
5+ex2+ydydx=ex
dy2+y=exex+5dx
ln(y+2)=ln(ex+5)+C
(y+2)(ex+5)=C

y(0)=1
(1+2)(e0+5)=C
C=18
y+2=18ex+5
At x=ln13,
y+2=1813+5=1
y=1

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Applications of Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon