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Question

If yield of third reaction is 90 percent, then moles of CO2 formed, when 2.06×103gm NaBr is formed, is:

A
20
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B
10
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C
40
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D
none
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Solution

The correct option is B 10
Balanced chemical equations are -
Fe+Br2FeBr2
3FeBr2+Br2Fe3Br8
Fe3Br8+4Na2CO38NaBr+4CO2+Fe3O4
When 8 moles of NaBr are formed, 4 moles of carbon dioxide are formed.
The number of moles of carbon dioxide formed is 2.06×103102.9×48=10.

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