Question

If you have several $2.0\mu F$ capacitors, each capable of withstanding $200volts$ without breakdown how would you assemble a combination having minimum number of capacitors and of given equivalent capacitance which capable of withstanding $1000volts$ ;
(A) $0.40\mu F$
(B) $1.2\mu F,$ capable of withstanding $1000$ volts.

Answer 1

(a) Use 5 cap. in series

So, $\frac{1}{C}=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}$

$\frac{1}{C}=\frac{5}{2}$

$C=0.4f$

(b) Now above series line make these three lines in parallel

$Ceg=0.4+0.4+0.4$

$=12\mu F$