Question

If you roll two number cubes, then what is the chance that at least one 4 is rolled?

• A. $\frac{13}{36}$
• B. $\frac{12}{36}$
• C. $\frac{11}{36}$
• D. $\frac{15}{36}$

Answer 1

The correct option is C $\frac{11}{36}$


Total number of possible outcomes from the sample space$=36$
Total number of favorable outcomes where at least one 4 is rolled $=11$
Probability of event $=\frac{11}{36}$