If you set up the seventh harmonic on a string fixed at both ends, how many

nodes and antinodes are set up in it

[AMU 2000]

8, 7

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7, 7

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8, 9

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9, 8

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Solution

The correct option is A
8, 7

String will vibrate in 7 loops so it will have 8 nodes 7 antinodes.

Number of harmonics = Number of loops

Number of antinodes = 7

Hence number of nodes = Number of antinodes + 1

=7+1=8

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Similar questions

If you set up the seventh harmonic on a string fixed at both ends, how many nodes and antinodes are set up in it.

If you set up the ninth harmonic on a string fixed at both ends, its frequency

compared to the seventh harmonic

[AMU (Engg.) 2000]

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