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Physics

Latent Heat

If you take w...

Question

If you take water of mass 'm' and specific heat 's' in one container and raise its temperature from 20°C to 60°C and oil that has a mass of '2m' and a specific heat of '2s' in another container and raise its temperature form 20°C to 40 °C, what will be the ratio of heat supplied to the water to the heat supplied to the oil?

1:2

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2:1

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1:4

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4:1

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Solution

The correct option is A
1:2

$\frac{Q w}{Q o}$ = $\frac{m s (60 - 20)}{2 m 2 s (40 - 20)}$

= $\frac{m s (40)}{2 m 2 s (20)}$

= $\frac{1}{2}$

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The correct option is A 1:2 QwQo=ms(60−20)2m2s(40−20) =ms(40)2m2s(20) =12

The correct option is A
1:2

$\frac{Q w}{Q o}$ = $\frac{m s (60 - 20)}{2 m 2 s (40 - 20)}$

= $\frac{m s (40)}{2 m 2 s (20)}$

= $\frac{1}{2}$