If Young's double slit experiment of light, interference is performed in water, which one of the following is correct?
A
Fringe width will decrease
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B
Fringe width will increase
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C
There will be no fringe
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D
Fringe width will remain unchanged
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Solution
The correct option is B Fringe width will decrease If Young's double slit experiment is performed in water of refractive index μμ instead of air, the wavelength of light change from λλ to (λ/μ)(λ/μ) ∴β′=Dd(λμ)=βμ∴β′=Dd(λμ)=βμ Fringe width reduces and becomes (1/μ)(1/μ) times of its value in air.