Question

If your eye glasses have focal length +60 cm, what is your near point?

Answer 1

Given:
$f=+60cm$
As f is positive, it is a case of Hypermetropia. We need the object to be at near point of distinct vision for a normal eye i.e, at 25cm.

Let $u=-25cm$ (near point of normal eye)
According to Lens formula:
$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
$\frac{1}{60}=\frac{1}{v}+\frac{1}{25}$
$v=-43cm$

Thus near point is 43 cm.