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Question

If |z1|=2,arg(z1)=π6, then z is

A
3+i
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B
3+1+i
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C
31+i
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D
13i
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Solution

The correct option is B 3+1+i
From Euler's form of complex number,
z1=|z1|eiarg(z1),
Where |z1|=2,arg(z1)=π6
z1=2eiπ/6z=2(cosπ6+isinπ6)+1z=3+1+i

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