wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If z1=5+12i and |z2|=4, then

A
Maximum value of |z1+iz2| is 17
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Minimum value of |z1+(1+i)z2| is 1342
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Minimum value of ∣ ∣ ∣ ∣z1z2+4z2∣ ∣ ∣ ∣ is 134
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Maximum value of ∣ ∣ ∣ ∣z1z2+4z2∣ ∣ ∣ ∣ is 133
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A Maximum value of |z1+iz2| is 17
B Minimum value of |z1+(1+i)z2| is 1342
D Maximum value of ∣ ∣ ∣ ∣z1z2+4z2∣ ∣ ∣ ∣ is 133
Here, |z1+iz2||z1|+|iz2|13+417

|z1+(1+i)z2|||z1||(1+i)z2||1342

Now, |z2|4|z2|z2+4z2|z2|+4|z2|
3z2+4z25
|z1|=13
∣ ∣ ∣ ∣z1z2+4z2∣ ∣ ∣ ∣ has minimum value as 135 and maximum value as 133

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon