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Byju's Answer
Standard XII
Mathematics
Equality of 2 Complex Numbers
If | z |=1 an...
Question
If |z|=1 and arg
(
z
)
=
π
4
then which of the following is /are true?
A
Modulus of
(
z
5
−
i
z
)
is
√
2
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B
Modulus of
(
z
4
−
i
z
)
is 1
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C
Principal argument of
(
z
5
−
i
z
)
is
π
4
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D
Principal argument is
(
z
5
−
i
z
)
is
π
2
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Solution
The correct options are
A
Modulus of
(
z
5
−
i
z
)
is
√
2
D
Principal argument is
(
z
5
−
i
z
)
is
π
2
Let
z
=
e
i
π
4
z
5
−
i
z
=
e
i
5
π
4
−
i
.
e
i
π
4
=
(
−
1
−
i
)
e
i
π
4
So
|
z
5
−
i
z
|
=
√
2
arg
(
z
5
−
i
z
)
=
−
3
π
4
+
π
4
=
−
π
2
z
4
−
i
z
=
e
i
π
−
i
.
e
i
π
4
So
|
z
5
−
i
z
|
≠
√
2
Suggest Corrections
0
Similar questions
Q.
If
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Q.
If
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having the least positive argument is
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