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Byju's Answer
Standard XII
Mathematics
Modulus of a Complex Number
If z1 and ...
Question
If
z
1
and
z
2
are two complex numbers, then prove that
|
z
1
|
+
|
z
2
|
=
∣
∣
∣
z
1
+
z
2
2
+
√
z
1
z
2
∣
∣
∣
+
∣
∣
∣
z
1
+
z
2
2
−
√
z
1
z
2
∣
∣
∣
Open in App
Solution
R
H
S
=
∣
∣
∣
z
1
+
z
2
+
2
√
z
1
z
2
2
∣
∣
∣
+
∣
∣
∣
z
1
−
1
z
2
−
2
√
z
1
z
2
2
∣
∣
∣
=
|
√
z
1
+
√
z
2
|
2
2
+
|
√
z
1
−
√
z
2
|
2
2
=
|
z
1
|
+
|
z
2
|
+
2
√
z
1
z
2
+
|
z
1
|
+
|
z
2
|
−
2
√
z
1
z
2
2
=
2
(
|
z
1
|
+
|
z
2
|
2
)
=
|
z
1
|
+
|
z
2
|
=
L
H
S
Q.E.D
Suggest Corrections
0
Similar questions
Q.
If
z
1
and
z
2
are complex numbers and
u
=
√
z
1
z
2
, then prove that
|
z
1
|
+
|
z
2
|
=
∣
∣
∣
z
1
+
z
2
2
+
u
∣
∣
∣
+
∣
∣
∣
z
1
+
z
2
2
−
u
∣
∣
∣
.
Q.
If
z
1
and
z
2
are two complex numbers such that
z
1
≠
z
2
and
|
z
1
|
=
|
z
2
|
, then
z
1
+
z
2
z
1
−
z
2
may be
Q.
For any two non-zero complex numbers
z
1
,
z
2
prove the inequality
(
|
z
1
|
+
|
z
2
|
)
∣
∣
∣
z
1
|
z
1
|
+
z
2
|
z
2
|
∣
∣
∣
≤
2
(
|
z
1
|
+
|
z
2
|
)
Q.
lf
z
1
and
z
2
are two complex numbers such that
|
z
1
|
=
|
z
2
|
+
|
z
1
−
z
2
|
, then
arg
(
z
1
)
−
arg
(
z
2
)
Q.
If
z
1
and
z
2
are two non-zero complex numbers such that
|
z
1
−
z
2
|
=
|
|
z
1
|
−
|
z
2
|
|
then
arg
(
z
1
)
−
arg
(
z
2
)
=
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