If z1 and z2 are two non-zero complex numbers such that ∣∣∣z1−z2z1+z2∣∣∣=1, then
A
z2=ikz1,k∈R
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B
z2=kz1,k∈R
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C
z2=z1
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D
z1z2 is real
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Solution
The correct option is Az2=ikz1,k∈R ∣∣∣z1−z2z1+z2∣∣∣=1 ⇒∣∣
∣
∣∣z1z2−1z1z2+1∣∣
∣
∣∣=1⇒∣∣∣z1z2−1∣∣∣=∣∣∣z1z2+1∣∣∣ ⇒ Locus of z1z2 is the perpendicular bisector of line segment joining (1,0) and (−1,0) ∴z1z2=ai,a∈R⇒z2=1aiz1=−iaz1⇒z2=ikz1(−1a=k∈R)