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Byju's Answer
Standard XII
Mathematics
Condition for Coplanarity of Four Points
If z1 and ...
Question
If
z
1
and
z
2
are two non-zero complex numbers such that
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
. then
A
z
1
¯
¯¯¯
¯
z
2
is purely imaginary
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B
z
1
/
z
2
is purely imaginary
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C
z
1
¯
¯
¯
z
2
+
¯
¯
¯
z
1
z
2
=
0
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D
0
,
z
1
,
z
2
are the vertices of a right triangle
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Solution
The correct option is
A
z
1
¯
¯¯¯
¯
z
2
is purely imaginary
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
+
2
R
e
(
z
1
¯
z
2
)
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
⇒
R
e
(
z
1
¯
z
2
)
=
0
Thus,
z
1
¯
z
2
is purely imaginary. So, A is the correct option.
Since
1
z
2
=
¯
z
2
|
z
2
|
2
z
1
z
2
=
z
1
¯
z
2
|
z
2
|
2
Since the magnitude of a complex number is a real number
⇒
Option B is also correct.
Suggest Corrections
0
Similar questions
Q.
If
z
1
,
z
2
are complex numbers such that
2
z
1
3
z
2
is purely imaginary number, then find |
z
1
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2
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+
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Q.
If
z
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and
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2
are two complex numbers such that
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<
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then prove that
∣
∣
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z
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¯
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¯
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∣
∣
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Q.
Let
z
1
and
z
2
be complex numbers such that
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≠
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2
and
|
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|
=
|
z
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|
.
If
z
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has positive real part and
z
2
has negative imaginary part, then show that
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+
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Q.
Let
z
1
and
z
2
be complex numbers such that
z
1
≠
z
2
and
|
z
1
|
=
|
z
2
|
.
If
R
e
(
z
1
)
>
0
and
I
m
(
z
2
)
<
0
,
then
z
1
+
z
2
z
1
−
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2
is
Q.
If
z
1
and
z
2
are complex numbers, prove that
|
z
1
+
z
2
|
2
=
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z
1
|
2
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2
if and only is
z
1
¯
z
2
is pure imaginary.
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