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Question

If |z1+z2|=|z1|+|z2|, then argz1argz2=

A
π2
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B
π2
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C
0
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D
π
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Solution

The correct option is B 0
|z1+z2|=|z1|+|z2|
On squaring,
|z1|2+|z2|2+2|z1||z2|cosθ=|z1|2+|z2|2+2|z1||z2|
where, θ=argz1argz2
cosθ=1
θ=0
Hence, option C is correct.


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