If |z1|=|z2|=|z3|=1 and z1,z2,z3 are represented by the vertices of an equilateral triangle. Then
A
z1+z2+z3
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B
z1z2+z2z3+z3z1=1
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C
z1+z2+z3=1
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D
none of these
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Solution
The correct option is D none of these Angle subtended by a chord on centre is double of that subtended on circumference by the same chord. Solution: z2=z1e2πi/3=z1w