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Question

If z1, z2, z3 are vertices of an equilateral triangle ABC such that |z1−i|=|z2−i|=|z3−i|, then |z1+z2+z3| equals to

A
33
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B
3
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C
3
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D
133
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Solution

The correct option is C 3
Given that,
|z1i|=|z2i|=|z3i|
Hence, z1, z2, z3 lie on a circle whose centre is i.
Also, given that the triangle is equilateral. Hence, centroid and circumcenter coincides.
z1+z2+z33=i
|z1+z2+z3|=3

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