The correct option is D the imaginary axis
Given that
|z2−1|=|z2|+1⇒|z2+(−1)|=|z2|+|−1|
It shows that the origin, -1, and z2 lie on a line and z2 and -1 lie on one side of the origin. Therefore, z2 is a negative number. Hence, z will be purely imaginary. So we can say that z lies on the y-axis.