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Question

If z=2+3i, then the expression z4z3+10z2+3z5 reduces to a real number equal to

A
122
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B
122
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C
160
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D
160
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Solution

The correct option is B 122
We know that z=2+3i
z4z3+10z2+3z5
z2=(2+3i)2=4+12i9=12i5
z3=(2+3i)3=827i+36i54=9i46
z4=(2+3i)4=119120i
z4z3+10z2+3z5
=119120i9i+46+120i505+6+9i
=122.
Hence, the answer is 122.

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