If -z-2- argz-6- then z -

The correct option is B √(3)+i z = r cosθ + r sinθ i z = 2 cos (π6) + 2 sin (π6) i z = 2 (√(3)2) + 2 ( 12) i #160; z = √(3) #160 ...

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Section Formula

If |z|=2, a...

Question

If |z|=2, $a r g z = \frac{π}{6}$ , then $z =$

\sqrt{3} - i

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\sqrt{3} + i

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1 + \sqrt{3} i

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1 - \sqrt{3} i

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| z - 3 i | = 3

a r g z \in (0, \frac{π}{2})

c o t (a r g z) - \frac{6}{z}

If |z - 3i| = 3, (where i = $\sqrt{- 1}$ ) and argz $\in (0, \frac{π}{2})$ , then cot(arg(z)) - $\frac{6}{z}$ is equal to

a r g (z + i) = \frac{π}{4}

| z + 4 - 3 i | + | z - 4 + 3 i |

Z = \frac{1 - \sqrt{3} i}{1 + \sqrt{3} i}

a r g (z) .

a r g (z - 2 - 3 i) = \frac{π}{2}

z

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