IF Z = 26, NET = 39 then NUT = ?

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Solution

The correct option is C 55
Z = 26 position number in alphabetical series NET = 14 + 5 + 20 = 39
Similarly NUT = 14 + 21 + 20 = 55
So the answer is (3)

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Similar questions

$(\frac{7}{- 26} + \frac{16}{39}) = ?$

(a) $\frac{11}{78}$

(b) $\frac{- 11}{78}$

(d) $\frac{- 11}{39}$

2 - \frac{11}{39} + \frac{5}{26}

\frac{16}{39} + \frac{9}{- 26}

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