Question

if $z+3-2i$ is purely imaginary then

• A. $Rez=-3$
• B. $Imz=2i$
• C. $Rez=3$
• D. $Imz=-2i$

Answer 1

The correct option is A $Rez=-3$

Let $z=a+ib$

$z+3-2i=a+3+i(b-2)$

For a equation to be purely imaginary, its real part should be equal to zero.

It is purely imaginary so $a+3=0$

$a=-3$