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Question

If |z|=4, argz=5π6, then z=

A
3+i
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B
3+i
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C
2(3+i)
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D
2(3+i)
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Solution

The correct option is D 2(3+i)
For any complex number
z=|z|eiarg(z)
Here |z|=4 and arg(z)=5π6.
Hence, z=|z|eiarg(z)
=4ei5π6
=4(cos(5π6)+isin(5π6))
=4(3+i2)
=2(3+i)

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