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Question

If z=4cosθ(cosθ+isinθ), then locus of z is

A
circle with centre (4,0)
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B
circle with centre (2,0)
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C
ellipse
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D
hyperbola
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Solution

The correct option is B circle with centre (2,0)
Let, z=x+iy
x+iy=4cos2θ+2sin2θi
x=2(1+cos2θ),y=2sin2θ
x2=2cos2θ,y=2sin2θ

x22=cos2θ,y2=sin2θ

squaring and adding we get,

cos22θ+sin22θ=1
(x2)2+y2=4. which is circle centred at (2,0)

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