1
Question
If z=4+i√7, then find the value of |z3−4z2−9z+91|.
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Solution
z=4+i√7
or z−4=i√7
On squaring, we get z2−8z+16=−7
⇒z2−8z+23=0
Now |z3−4z2−9z+91|=|(z2−8z+23)(z+4)−1|=1
Ans: 1
z=4+i√7
or z−4=i√7
On squaring, we get z2−8z+16=−7
⇒z2−8z+23=0
Now |z3−4z2−9z+91|=|(z2−8z+23)(z+4)−1|=1
Ans: 1
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