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Question

If |z|<4, then |iz+34i| is less then

A
4
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B
5
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C
9
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D
6
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Solution

The correct option is C 9
Given, |z|<4......(1).
Now
|iz+34i||iz|+|(34i)| [ Using standard inequility of sum of two complex number]
or, |iz+34i||z|+5 [ Since |iz|=|z|]
or, |iz+34i|<4+5 [ Using (1)]
or, |iz+34i|<9.

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