If |z−4i|+|z+4i|=10, then the equation of the locus of z is:
A
x225+y29=1
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B
x25+y29=1
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C
x225−y29=1
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D
x29+y225=1
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Solution
The correct option is Dx29+y225=1 Let z=x+iy √x2+(y−4)2+√x2+(y+4)2=10 ⇒x2+(y−4)2=100+x2+(y+4)2−20√x2+(y+4)2 ⇒400(x2+(y+4)2)=(100+16y)2=(100)2+2×100×16y+256y2 ⇒400x2+400y2+3200y+6400=(100)2+3200y+256y2 ⇒400x2+144y2=3600 ⇒x29+y225=1