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Question

If z=5+3i and the value of z4+9z3+26z214z+8 is k, where kR, then the value of k is

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Solution

z=5+3i(z+5)=3i(z+5)2=9z2+10z+34=0(1)

Now using equation (1), we get
z4+9z3+26z214z+8=z2(z2+10z+34)z38z214z+8=0z(z2+10z+34)+2z2+20z+8=2z2+20z+8=2(z2+10z+34)60=60k=60
k=60

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